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Analizando el bloque 1
Σ Fx = m₃ a
T = 6 a --------------( α )
Con todo el sistema
Σ Fx = (m₁ + m₂ + m₃) a
Fn = (m₁ + m₂ + m₃) a
72 N = (6 + 12 + 18) kg ( a )
72 N = 36 kg ( a )
a = 72 N / 36 kg = 2 m/s²
Por lo que sustituimos en ( α )
T = 6 a = 6 kg ( 2 m/s²) = 12 N