December 2018 1 14 Report
Si n E a Z+

2n \leqslant 2 {}^{n}
demostrar por induccion matematica

n=1 2<=2

n=k 2k<=2^k

n=k+1 2(k+1)<=2^k+1

como demuestro que es cierto llegue hasta:

2k*2<=2^k*2

4k<=2^k+1

y no se como continuar ayudaaaa

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