Question

Si log x= 3 y log y = 5, calcula

Answer 1

  logx=3  logy=5
a)  logxy=logx+logy=3+5=8
b)  log x^2/y=log x^2-log y=2logx-logy=2*3-5=6-5=1
c)  logx^logy=logy*logx=5*3=15
d)  lograiz3dexy^2=log(xy^2)^1/3=1/3logxy^2=1/3(logx+logy^2)=
     1/3(logx+2logy)=1/3(3+2*5)=1/3*13=13/3
e)logy/raiz4dex=logy/x^1/4=logy-logx^1/4=logy-1/4logx=5-1/4*3=
    =(5*4-3)/4=17/4
f) logy^log(xy)=log(xy)*logy=(logx+logy)*logy=(3+5)*5=8*5=40