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número menor= b
a×b= -48...(I)
a-b= 16....(II) despejando tenemos que:
a= 16+b (III)
reemplazamos (III) en (I)
(16+b )x b = -48
16b + b^2 = -48
Aplicamos aspa simple
b^2 + 16b + 48= 0
b+12= 0 y b+4= 0
b= -12 y b= -4
tomamos el mayor entonces b= -4
reemplazando en (III)
a= 16 + b
a= 16- 4
a= 12
R: -4 y 12
Y-X=16 (2) Y=16+X sustituir (1)
X(16+X)=-48
16X+X^2=-48
X^2+16X+48=0 X1=-4 X2=-12
12-(-4)=16
4-(-12)=16
Hay dos numeros por cada uno
X1=-4 X2=-12
y=16+X ==> y1=16-4=12
y2=16-12=4