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Perimetro = 2*L * 2A L = Largo A = Ancho
Area = L * A
27 = 2L + 2A (1)
44 = L * A (2)
De (2) Despejamos L
44 = L * A
44/A = L Este valor lo reemplazamos en (1)
27 = 2 * L + 2A
27 = 88/A + 2A
27 = 88/A + 2A²/A
27 = (88 + 2A²)/A
27A = 88 + 2A²
0 = 2A² + 88 - 27A
2A² - 27A + 88 = 0
Por formula.
x =[ - b +/-√(b² - 4ac)]/2a a = 2 , b = -27 , c = 88
x = [ - ( -27) +/-√((-27)² - 4(2)(44))]/2(2)
x = [ 27 +/- √(729 - 704)]/4
x = 27 + / - √377]/4
x1 = (27 + √25)/4
x1 = (27 + 5)/4
x1 = (32/4)
x1 = 8
o
x2 = (27 - √25)/4
x2 = (27 - 5)/4
x2 = 22/4
x2 = 5,5
Respuesta.
El largo = 8m
Ancho = 5,5m