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Se suman todos los factores que tengan la misma variable, en este caso la variable es "a"
(1+2+3+4+5+6+7+8+9)a=3bc
45a=3bc
Entonces:
45a=3bc
(45a)÷3=bc
15a=bc
a=(bc)÷15
b=(15a)÷c
c=(15a)÷b
a+b+c
((bc)÷15)+((15a)÷c)+((15a)÷b)
((c^2×b^2)+(225ab)+(225ac))÷(15cb)
(bc÷15)+(15a÷c)+(15a÷b)
a+b+c