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Diketahui :
S ( jarak benda ) = 25 cm
S' ( jarak bayangan ) = 2,5 cm ( kita ingin agar bayangan jatuh tepat di retina )
Ditanya :
F (fokus lensa mata) ?
Jawab =
1/f = 1/S + 1/S'
1/f = 1/25 + 1/2,5
1/f = 1/25 + 10/25
1/f = 11/25
f = 2,27 cm
Sifat bayangan
diperkecil, maya, tegak
f=2/50+5/50
f=7/50