OB = r = 7 cm
[tex]\sf L\:arsir=L\:lingkaran \times \frac{360^{\circ}-(90^{\circ}+120^{\circ})}{360^{\circ}} \\\\=\pi r^{2} \times \frac{360^{\circ}-210^{\circ}}{360^{\circ}} \\\\=\frac{22}{7} \times 7^{2} \times \frac{150^{\circ}}{360^{\circ}} \\\\=22 \times 7 \times \frac{5}{12} \\\\=11 \times 7 \times \frac{5}{6} \\\\=64,1667\:cm^{2}[/tex]
Maka luas daerah yang diarsir adalah 64,1667 cm².
Penjelasan dengan langkah-langkah:
luas arsir
22/7 x 7 x 7 x 360-210/360
22 x 7 x 15/36
64,1667 cm2
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Verified answer
OB = r = 7 cm
[tex]\sf L\:arsir=L\:lingkaran \times \frac{360^{\circ}-(90^{\circ}+120^{\circ})}{360^{\circ}} \\\\=\pi r^{2} \times \frac{360^{\circ}-210^{\circ}}{360^{\circ}} \\\\=\frac{22}{7} \times 7^{2} \times \frac{150^{\circ}}{360^{\circ}} \\\\=22 \times 7 \times \frac{5}{12} \\\\=11 \times 7 \times \frac{5}{6} \\\\=64,1667\:cm^{2}[/tex]
Maka luas daerah yang diarsir adalah 64,1667 cm².
Penjelasan dengan langkah-langkah:
luas arsir
22/7 x 7 x 7 x 360-210/360
22 x 7 x 15/36
64,1667 cm2