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A2 = π . 1/4 . 4 d1^2
A2 = 4 ( π . 1/4 . d1^2 )
π . 1/4 . d1^2 = A1,
A2 = 4 ( π . 1/4 . d1^2 ) -> subtitusikan π
. 1/4 . d1^2 dengan A1
A2 = 4 A1
R2 = ρ . L2 / A2 -> (hambatan jenis tetap sama karena bahan pembuat kawat tidak berubah)
R2 = ρ . [(1/2) L1] / [4 A1]
R2 = [(1/2) / 4 ] [ ρ . L1 / A1 ]
R2 = 1/8 ( ρ . L1 / A1 )
Karena ρ . L1 / A1 = R1 maka :
R2 = 1/8 ( ρ . L1 / A1 ) -> subtitusi ρ .
L1 / A1 dengan R1
R2 = 1/8 . R1
R1 = 24 ohm , maka :
R2 = 1/8 . 24 ohm
R2 = 3 ohm
oke? jadikan terbaik ^_^