Question

Seorang penderita hipermetropi berkaca mata 3 dioptri. tentukan titik dekat mata orang tersebut?
jawab yah

Answer 1

S = jarak baca normal = 25
s' = - titik dekat mata penderita rabun dekat

P= 100/f
f= 100/3

1/s + 1/s' = 1/f
1/25  + 1/s' = 3/100
1/s' = 3/100-1/25
1/s' = 3/100-4/100
1/s' = -1/100
s' = -100