Question

Senyawa NaOH punya normalitas 0,2N berapa molar zat tersebut? (V=6,25ml)

Answer 1

N = massa/be X 1000/6, 25

0,2 = massa/40 X 16.000

0,2 X 40/16000 = massa

massa = 0,0005 gr

M = gr/mr X 1000/v(ml)

M = 0.0005/40 X 1000/6,25

M = 0.0005/40 X 16000

M = 0,0005 X 400

M = 0,2 M