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sabemos que sen 50 = opuesto / hipotenusa = o/h ok
⇒ sen² 50 = o²/h² ok
cos 50 = adyacente / hipotenusa = a / h
cos² 50 = a²/ h²
ahora
sen² 50 + cos² 50 = o²/ h² + a² / h²
= ( o² + a²) / h²
= h² / h² esto espitagoras h² = o² + a²
= 1
suerte
sen 50 = 0,766
sen^2 50 = 0,5866
cos 50 = 0,643
cos^2 50 = 0,4134
(sen^2 50)(cos^2 50) = (0,5866)(0,4134)
= 0,2425 RESULTADO FINAL