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Verified answer
1a.log (3x - 1) = log 5
3x - 1 = 5
3x = 6 ,x = 2
Syarat
3x - 1 > 0
x > ⅓
HP :{ 2 }
2a.
⁵log x² = ⁵log 4x + 1
⁵log x² - ⁵log 4x = 1
⁵log (x²/4x) = ⁵log 5
x/4 = 5
x = 20
Syarat
x > 0
HP : {20}
3a.
log(log (x + 3)) = log 2
log (x + 3) = 2
x + 3 = 10²
x = 100 - 3
x = 97
Syarat
x + 3 > 0 , x > -3
HP :{97}
4a.
⁴log 2^x = x
4^x = 2^x
x = 0
HP : {0}
5a.
³log²x + 9 • ³ log x - 10 = 0
(³log x + 10)(³log x - 1) = 0
³log x = -10 [TM]
atau
³log x = 1
³log x = ³log 3
x = 3
HP : {3}