A. Panjang Busur = 45°/360° × π × d
= 1/8 × 22/7 × 42
= 16,5 cm
B. LJ : L₀ = α : 360⁰
1.256 : L₀ = 90⁰ : 360⁰
1.256 : L₀ = 1 : 4
L₀ = 1.256 × 4
L₀ = 5.024
πr² = 5.024
3,14 r² = 5.024
r² = 5.024/3,14
r² = 1.600
r = √1.600
r = 40 cm
Jadi, jari-jari lingkaran tersebut adalah 40 cm.
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A. Panjang Busur = 45°/360° × π × d
= 1/8 × 22/7 × 42
= 16,5 cm
B. LJ : L₀ = α : 360⁰
1.256 : L₀ = 90⁰ : 360⁰
1.256 : L₀ = 1 : 4
L₀ = 1.256 × 4
L₀ = 5.024
πr² = 5.024
3,14 r² = 5.024
r² = 5.024/3,14
r² = 1.600
r = √1.600
r = 40 cm
Jadi, jari-jari lingkaran tersebut adalah 40 cm.
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