Question

Segitiga siku siku, sisi miringnya (3a +4), sisi lainnya (3a +2), (a +4)
a. tentukan nilai a
b. hitung keliling segitiga

Answer 1

Verified answer

K=A+b+c
=(3a+4)+(3a+2)+(a+4)
=3a+3a+a+4+2+4
=7a+10

Kelilingnya adalah 7a+10

Answer 2

Diket :
X = (3a+2)
Y = (a+4)
Z = (3a+4)

Jawab :
Z = akar X^2+Y^2
3a+4 = akar (3a+2)^2+(a+4)^2
(3a+4)^2 = (9a^2+12a+4)+(a^2+8a+16)
9a^2+24a+16 = 10a^2+20a+20
a^2-4a+4 = 0
(a-2)(a-2) = 0
a = 2

Keliling :
K = x+y+z
K = (3a+2)+(a+4)+(3a+4)
K = 7a+10

K = 7(2)+10
K = 14+10
K = 24 cm

Pembuktian :
X = (3a+2) = 3(2)+2 = 8
Y = (a+4) = 2+4 = 6
Z = (3a+4) = 3(2)+4 = 10
Pythagoras : 6,8,10