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Step-1 pandang ΔABD
Tan 30° = 1/√3
BD / BA = 1/√3
1 / BA = 1/√3
BA = √3
Step-2 mencari tan 75°
Tan 75° = tan (45° + 30°)
= [tan 45° + tan 30°] / [1 - (tan 45°)(tan 30°)]
= [1 + 1/√3] / [1 - 1/√3] ... Kalikan atas-bawah dengan √3
= [1 + √3] / [√3 - 1].. Rasionalkan
= [1 + 2√3 + 3] / 2
= 2 + √3
Step-3 pandang ΔABC
Tan 75° = BC / BA
2 + √3 = BC / √3
BC = √3.[2 + √3]
BC = 3 + 2√3
Final step
Mencari CD
CD = BC - BD
CD = 3 + 2√3 - 1
∴ CD = 2 + 2√3