Sebuah trafo efisiensi 75%, tegangan inputnya 220 V dan tegangan lututnya 110 V. jika kuat arus primer yang mengalir 2 A, kuat arus seminarnya adalah
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Η = Pout/Pin 0,75 = Is*110/2*220 0,75 = Is/4 Is = 0,75*4 = 3A
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N = P out / P in × 100 % n = Vs × Is / Vp × Ip × 100% 75 % = 110 × Is / 220 × 2 × 100% 75 % = Is / 4 × 100% 75 % / 100 % = Is / 4 3/4 = Is/4 4 Is = 12 Is = 12/4 Is = 3 A
0,75 = Is*110/2*220
0,75 = Is/4
Is = 0,75*4 = 3A
n = Vs × Is / Vp × Ip × 100%
75 % = 110 × Is / 220 × 2 × 100%
75 % = Is / 4 × 100%
75 % / 100 % = Is / 4
3/4 = Is/4
4 Is = 12
Is = 12/4
Is = 3 A