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Verified answer
Diket :Vp = 200 v
Vs = 30 v
Ip = 2 A
Is = 10 A
dit : ef , Pp , Ps & Ph ?
jwb :
# efisiensi
ef = ( Is . Vs / Ip . Vp ) . 100%
ef = ( 10 . 30 / 2 . 200 ) . 100%
ef = ( 300 / 400 ) . 100%
ef = 75 %
# daya primer
Pp = Ip . Vp
Pp = 2 . 200
Pp = 400 watt
# daya sekunder
Ps = Is . Vs
Ps = 10 . 30
Ps = 300 watt
# daya yg hilang
Ph = Pp - Ps
Ph = 400 - 300
Ph = 100 watt