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Verified answer
Diket :Vp = 220 v
Ip = 4 A
t = 20 menit = 1200 s
Wh = 10.400 j ( rugi energi )
dit : efisiensi
jwb :
# Energi primer
Wp = Ip . Vp . t
Wp = 4 . 220 . 1200
Wp = 1.056.000 joule
# Energi sekunder
Ws = Wp - Wh
Ws = 1.056.000 - 10.400
Ws = 1.045.600 joule
# efisiensi
ef = ( Ws / Wp ) . 100%
ef = (1.045.600 / 1.056.000 ) . 100%
ef = 0,99 . 100%
ef = 99%
Jadi efisiensinya 99%