Sebuah trafo dengan perbandingan jumlah lilitan primer dan lilitan sekunder 25 : 3, memiliki tegangan primer 2.500 volt arus sekunder 10 A . tentukan besarnya daya sekunder pada trafo tersebut!
kerie
Np : Ns = 25 : 3 Vp = 2500 V Ip = 10 A Ps =?
a. cari Vs Vp/Vs = Np/Ns 2500/Vs = 25/3 Vs = (2500.3)/25 Vs = 300 V
b. cari Is (Ingat dalam trafo Is/Ip = Vp/Vs = Np/Ns) Is/Ip = Np/Ns Is/10 = 25/3 Is = (25.10)/3 Is = 250/3 A
c. cari Ps Ps = Vs. Is Ps = 300. 250/3 Ps = 25000 W = 25 kW
Vp = 2500 V
Ip = 10 A
Ps =?
a. cari Vs
Vp/Vs = Np/Ns
2500/Vs = 25/3
Vs = (2500.3)/25
Vs = 300 V
b. cari Is (Ingat dalam trafo Is/Ip = Vp/Vs = Np/Ns)
Is/Ip = Np/Ns
Is/10 = 25/3
Is = (25.10)/3
Is = 250/3 A
c. cari Ps
Ps = Vs. Is
Ps = 300. 250/3
Ps = 25000 W = 25 kW