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r₁=8i+2j
r₂=2i+6j
Ditanyakan:
a.Vektor posisi?
b.arah vektor?
Dijawab:
a.vektor posisi:
r=r₂-r₁
=(2i+6j)-(8i+2j)
=-6i+4j
b.Arah vektor:
tanα=r₂
r₁
= 4
-6
=-0,66
α =arc tan⁻¹(0,66)
=-33,7°
=360+(-33,7)
=326,3° berlawanan jarum jam ya