Question

Sebuah tabung memiliki jari jari 21 cm, tinggi 50 cm
tentukan

Volume ?
Luas permukaan ?
Luas selimut ?
__________________________

Selamat kang arifin​

Answer 1

Sebuah Tabung memiliki jari' 21 cn , dan tinggi 50 Cm

____________________

Volume Tabung

V = π × r^2 × t

V = 22/7 × 21 × 21 × 50

V = 22 × 3 × 21 × 50

V = 69.300 Cm^3

Luas Permukaan Tabung

Lp = 2πr( r + t )

Lp = 2 × 22/7 × 21 × ( 21 + 50 )

Lp = 2 × 22 × 3 × 71

Lp = 9.372 Cm^3

Luas Selimut Tabung

LS = 2πrt

Ls = 2 × 22/7 × 21 × 50

Ls = 2 × 22 × 3 × 50

La = 6.600 Cm^3

Answer 2

DIKETAHUI :

1. R = 21 CM
2. T = 50 CM

TENTUKAN :

V DAN L.P DAN L.S

JAWAB :

V = π × R × R × T

= 22/7 × 21 CM × 21 CM × 50 CM

= 22/7 × 21 × 1.050 CM

= 22/7 × 22.050

= 22 × 3.150

= 69.300 CM³

L.P = 2 × π × R × [ R + T ]

= 2 × 22/7 × 21 CM × [ 21 CM + 50 CM ]

= 2 × 22/7 × 21 CM × 71 CM

= 2 × 22/7 × 1.491 CM

= 2 × 22 × 213

= 2 × 4.686 CM

= 9.372 CM²

L.S = 2 × π × R × T

= 2 × 22/7 × 21 CM × 50 CM

= 2 × 22/7 × 1.050 CM

= 2 × 22 × 150

= 2 × 3.300 CM

= 6.600 CM²