Sebuah prosma tegak yang alasnya berupa belah ketupat mempunyai keliling alas 20cm. jika panjang salah satu diagonal alasnya 6cm dan tinggi prisma 8cm, volume prisma tersebut adalah... pake caranya yaaa
azifa15
Keliling alas = 20cm slh stu diagonal = 6 diagonal satunya = 8
v prisma = 1/2.d1.d2.t = 1/2.6.8.20 =480cm2
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LailiaMahmudah
K = 4s 20 = 4s s = 5cm |\5cm |_\ 3cm ⇒ 5² - 3² √25-9 =√16 = 4cm ⇒Jadi diagonal yg lain = 4x2 = 8cm
⇔ volume = LA x t = 1/2.d1.d2 x t = 1/2.6.8 x 8 = 192cm³
slh stu diagonal = 6
diagonal satunya = 8
v prisma = 1/2.d1.d2.t
= 1/2.6.8.20
=480cm2
20 = 4s
s = 5cm
|\5cm
|_\
3cm
⇒ 5² - 3²
√25-9 =√16 = 4cm
⇒Jadi diagonal yg lain = 4x2 = 8cm
⇔ volume = LA x t
= 1/2.d1.d2 x t
= 1/2.6.8 x 8
= 192cm³