Sebuah prisma tegak alasnya berbentuk belah ketupat dengan panjang diagonal 12 cm dan 16 cm. jika seluruh permukaan prisma 392 cm2, volume prisma adalah
jennylimm28
S alas^2= (1/2 d1)^2+(1/2 d2)^2 s alas^2 = 6^2+8^2 s alas^2 = 36+64 s alas^2= 100 s alas = 10 cm
Lp = 2 La + Ls 392 = 2 (1/2 x d1x d2) + 4 (s alas)(t) 392 = d1xd2 + 4 (10)(t) 392 = 12x16 + 40 (t) 392 = 192 + 40 (t) 200= 40(t) t = 5 cm
V= La X t V= 1/2 (d1)(d2)X t V= 1/2 (12)(16) (5) V= 480 cm^3
s alas^2 = 6^2+8^2
s alas^2 = 36+64
s alas^2= 100
s alas = 10 cm
Lp = 2 La + Ls
392 = 2 (1/2 x d1x d2) + 4 (s alas)(t)
392 = d1xd2 + 4 (10)(t)
392 = 12x16 + 40 (t)
392 = 192 + 40 (t)
200= 40(t)
t = 5 cm
V= La X t
V= 1/2 (d1)(d2)X t
V= 1/2 (12)(16) (5)
V= 480 cm^3