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daya (P) = 128 watt
hambatan (R) = 800 ohm
ditanya : kuat arus (I) ?
jawab:
P = I² x R
I² = P / R
I² = 128w / 800 ohm
I² = 0,16
I = √0,16
I = 0,4 A
jadi kuat arus pd pompa adalah 0,4 Ampere