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Bab : Pertidaksamaan Linear Satu Variabel
Diketahui :
- Panjang (p) = 2 × Lebar (l)
- Keliling (K) ≤ 24 cm
Ditanya :
- Lebar (l) ≤ ......?
- Panjang (p) ≤ ......?
Penyelesaian :
- Lebar (l) :
K ≤ 24
24 ≥ K
24 ≥ 2p + 2l
24 ≥ 2(2l) + 2l
24 ≥ 4l + 2l
24 ≥ 6l
6l ≤ 24
l ≤ 24 ÷ 6
l ≤ 4 cm
- Panjang (p) :
K ≤ 24
24 ≥ K
24 ≥ 2p + 2l
24 ≥ 2p + 2(1/2p)
24 ≥ 2p + p
24 ≥ 3p
3p ≤ 24
p ≤ 24 ÷ 3
p ≤ 8 cm
Maaf Kalau Salah