Sebuah pegas bila diberi gaya 50 N bartambah panjang 4 cm. besar energi potensial pegas ketika diberi beban 125 N adalah...J ?
semdavidtimothy
Cari konstanta pegas dulu ( K ) F = K delta x 50 = K 4 × 10 ^-2 K = 1250 lalu cri prtambhan pnjang ketika 125 N F = K delta x 125 = 1250 delta x delta x = 0.1 Ep pegas = 1/2 K x ^2 Ep pegas = 1/2 1250 10^-2 Ep pegas = 6.25 joule
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putrilarasantangF =k Δx 50 = k . 0,04 k = 1250 N/m Δx ketika 125 N F = k Δx 125 = 1250 Δx Δ x = 0.1 Ep pegas = k(Δx)²
F = K delta x
50 = K 4 × 10 ^-2
K = 1250
lalu cri prtambhan pnjang ketika 125 N
F = K delta x
125 = 1250 delta x
delta x = 0.1
Ep pegas = 1/2 K x ^2
Ep pegas = 1/2 1250 10^-2
Ep pegas = 6.25 joule
50 = k . 0,04
k = 1250 N/m
Δx ketika 125 N
F = k Δx
125 = 1250 Δx
Δ x = 0.1
Ep pegas = k(Δx)²
Ep pegas = 1250 (0,1)²
Ep pegas = 6.25 J
jadikan yg terbaik