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dit: vektor perpindahan materi pada t1 = 1s dan t2 = 2s
jawab : r = (3t²)i + (2t²+3t)j
t1= 1s
r1= (3(1)²)i + (2(1)²+3(1))j
r1= 3i + 5j
r = (3t²)i + (2t²+3t)j
t2= 2s
r2= (3(2)²)i + (2(2)²+3(2))j
= 12i + 14j
r = r2 - r1
= (12i + 14j) - (3i + 5j)
= (9i + 9j)