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panjang sisi alas =
K = 4 × p
48 = 4 × p
p = 48/4
p = 12
s = akar dari, (menggunakan phythagoras)
6 kuadrat + 8 kuadrat =
36 + 64 = 100
akar dari 100 = 10
s = 10
La = p × p
= 12 ×12
= 144 m kuadrat (m pangkat 2)
Ls = 4 (10 × 12)
-------
2
= 4 × 60
= 240 m kuadrat (m pangkat 2)
Lp = La + Ls
= 144 + 240
= 384
(I'm sorry if it isn't correct. And sorry for the imperfect formula because im using tablet not pc)
Ka = 4 × s
48 = 4 × s
s = 48 : 4
s = 12
a = t limas
= 8 cm
b = s : 2
= 12 cm : 2
= 6 cm
a² + b² = c²
8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c
t sisi tegak = c
= 10 cm
LP = La + Jumlah L sisi tegak
= s² + 4(1/2 × a × t)
= 12² + 4(1/2 × 12 × 10)
= 144 + 4(60)
= 144 + 240
= 384 cm²
Jadi luas permukaannya adalah 384 cm²