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Verified answer
SUHU• pemuaian
kubus
V₀
α
∆A → ∆t = __?
volume kubus
V₀ = r₀³
r₀ = ∛V₀
luas permukaan kubus
A₀ = 6 r₀²
A₀ = 6 (∛V₀)²
koefisien muai luas
β = 2α
pertambahan luas
∆A = A₀ β ∆t
∆t = ∆A / (A₀ β)
∆t = ∆A / (6 (∛V₀)² • 2α)
∆t = ∆A / (12 V₀^⅔ α)
∆t = (1/12) ∆A V₀^-⅔ α⁻¹