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Kategori: FisikaMateri: Cahaya
Kelas: XII SMA IPA
Kata kunci: Difraksi
Diketahui :
N = 12500 garis / cm
n = 1
θ = 30º
Ditanya :
λ = __ ?
Pembahasan :
d = 1/N
d = 1/12500 ×10⁻² = 8 × 10⁻⁷ m
d sin θ = n λ
λ = d sin θ / n
λ = (8 × 10⁻⁷ m) (0,5) / 1
λ = 4 × 10⁻⁷ m
= 400 nm
= 4000 Â
Jadi, panjang gelombang cahaya yang digunakan 4000 Amstrong.