Sebuah kerucut setinggi 30 cm memiliki keliling alas 66 cm. Volume kerucut tersebut adalah?
OXEStevenJoviW
T = 30 cm k alas = 2πr k alas = 66cm r alas = 33 : 22/7 r alas = 3 : 2/7 = 21/2 = 10,5 cm L alas = 314/100 X 10,5 X 10,5 L alas = 346,185 cm² V kerucut = 1/3 X 30 X 346,185 V kerucut = 3.461,85 cm³
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septyasy
Volume kerucut = 1/3 phi.r.t dan r (jari jari belum diketahui)
keliling alas = phi.r.r 66=3,14.r.r 66/3,14=r.r 21 =r.r r =4,58
k alas = 2πr
k alas = 66cm
r alas = 33 : 22/7
r alas = 3 : 2/7 = 21/2 = 10,5 cm
L alas = 314/100 X 10,5 X 10,5
L alas = 346,185 cm²
V kerucut = 1/3 X 30 X 346,185
V kerucut = 3.461,85 cm³
dan r (jari jari belum diketahui)
keliling alas = phi.r.r
66=3,14.r.r
66/3,14=r.r
21 =r.r
r =4,58
volume = 1/3 phi r t
volume= 1/3.3,14. 4,58 . 30
volume = 1,05 .137,4
volume =144,27 cm3
jaadi volumenya 144,27 cm3