Sebuah kerucut mempunyai panjang jari jari alas 35 cm dan volume 61.600 cm .tinggi lerucut tersebut adalah
bagusdwi1234
V=1/3x22/7xrxrxt 61600=1/3x22/7x35x35xt 61600=1/3x22x175xt 61600=1/3x3850xt 61600=550t t=61600/550 t=112 cm
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n45yw4v kerucut = 1/3 x 22/7 x r x r x t 61600 = 1/3 x 22/7 x 35 x 35 x t 61600 = 1/3x 22 x 175 x t 61600 = 1/3 x 3850 x t 61600 = 550 t t = 61600 / 550 t = 112 cm
61600=1/3x22/7x35x35xt
61600=1/3x22x175xt
61600=1/3x3850xt
61600=550t
t=61600/550
t=112 cm
61600 = 1/3 x 22/7 x 35 x 35 x t
61600 = 1/3x 22 x 175 x t
61600 = 1/3 x 3850 x t
61600 = 550 t
t = 61600 / 550
t = 112 cm
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