Question

sebuah kerucut memiliki volume 6.600cm³ dan tinggi 28cm. panjang diameter kerucut tersebut adalah....cm ​

Answer 1

[tex]\huge\color{cyan}{MATH}[/tex]

diketahui :

- v = 6.600 cm³

- t = 28 cm

ditanya :

diameter... ??

jawab :

[tex]v = \frac{1}{3} \times \frac{22}{7} \times r \times r \times t \\ 6.600 = \frac{1}{3} \times \frac{22}{7} \times {r}^{2} \times 28 \\ = \frac{1}{3} \times 6.600 \div 88 \times {r}^{2} \\ {r}^{2} = 75 \div 3 \\ r = \sqrt{25} = 5 \\ d = 5 \times 2 = 10[/tex]

kesimpulan :

jadi diameter kerucut adalah 10 cm

Answer 2

Diketahui :

Volume = 6.600 cm³

Tinggi = 28 cm

Ditanya :

Panjang diameter kerucut?

Jawab :

[tex]\sf \bf \sf v = \frac{1}{3} × πr² × t[/tex]

[tex]\sf \bf \sf 6.600 = \frac{1}{3} × \frac{22}{7} × r² × 28[/tex]

[tex]\sf \bf \sf 6.600 = \frac{1}{3} × \frac{22}{\cancel{7}} × r² × \cancel{28}^{\red{4}}[/tex]

[tex]\sf \bf \sf 6.600 = \frac{1}{3} × 22 × r² × 4[/tex]

[tex]\sf \bf \sf 6.600 = \frac{1}{3} × 22 × 4 × r²[/tex]

[tex]\sf \bf \sf 6.600 = \frac{1}{3} × 88 × r²[/tex]

[tex]\sf \bf \sf 6.600 × 3 = 88 × r²[/tex]

[tex]\sf \bf \sf 19.800 =88 × r²[/tex]

[tex]\sf \bf \sf \frac{19.800}{88}= r²[/tex]

[tex]\sf \bf \sf 225 = r²[/tex]

[tex]\sf \bf \sf \sqrt{225} = r[/tex]

[tex]\sf \bf \sf 15 \: cm= r[/tex]

• Menentukan diameter

[tex]\sf \bf \sf d = Jari - jari × 2[/tex]

[tex]\sf \bf \sf d = 15 \: cm × 2[/tex]

[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt d = 30 \: cm}}}}[/tex]

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