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Luas selimut = 188,4 cm²
Jari jari alas = 6 cm
Ditanya: volume kerucut?
Jawab:
Ls kerucut = phi . r . s
188,4 = 3.14 . 6 . s
188,4 = 18,84 . s
s = 188,4 : 18,84
s = 10
t² = \/ s² - r²
t² = \/ 10² - 6²
t² = \/ 100 - 36
t² = \/ 64
t = 8 cm
V.kerucut = 1/3 . Phi . r² . t
V.kerucut = 1/3 . 3,14 . 6 . 6 . 8
V.kerucut = 3,14 . 2 . 48
V.kerucut = 301,44 cm³
Ls : 188,4 cm
r : 6 cm
ditanya : V.k
jb :
Ls : phi.r.s
188,4 : 3.14.6.s
60 : 6. s
s : 10 cm
t2 : \/ s2 - r2
t2 : \/ 10`2 - 6`2
t2 : \/ 100 - 36
t2 : 64
t : 8 cm
vk : 1/3. phi. r2. t
vk : 1/3. 3.14. 6. 6. 8
Vk : 301.44 cm