Sebuah kerucut memiliki diameter 12 cm dan tinggi 8 cm.hitunglah: a.luas selimutnya b.luas sisi kerucut
5dregensleyer
R = 1/2 x 12 = 6 cm sisi mriring s = √ 6² + 8² = √ 36+ 64 = √100 = 10 cm luas selimut Ls = π x r x s = 3,14 x 6 x 10 = 188,4 cm² luas sisi Lp = La + Ls = ( π x r²) + 188,4 = (3,14 x 6 x 6) + 188,4 = 133,04 + 188,4 = 301,44 cm²
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vhetha
D = 12 cm r = 6 cm t = 8 cm s = √ 6² + 8² s = √ 36 + 64 s = √ 100 = 10 cm a) Ls = phi . r(r + s) = 3,14 . 6(6 + 10) = 301,44 cm² b) Ls = 4 . Ls ∆ = 4 . ½ . 12 . 10 = 240 cm²
sisi mriring
s = √ 6² + 8²
= √ 36+ 64
= √100
= 10 cm
luas selimut
Ls = π x r x s
= 3,14 x 6 x 10
= 188,4 cm²
luas sisi
Lp = La + Ls
= ( π x r²) + 188,4
= (3,14 x 6 x 6) + 188,4
= 133,04 + 188,4
= 301,44 cm²
r = 6 cm
t = 8 cm
s = √ 6² + 8²
s = √ 36 + 64
s = √ 100 = 10 cm
a) Ls = phi . r(r + s)
= 3,14 . 6(6 + 10)
= 301,44 cm²
b) Ls = 4 . Ls ∆
= 4 . ½ . 12 . 10
= 240 cm²