Sebuah dongkrak hidrolik memilki penghisap kecil berdiameter 5,5 cm dan diameter penghisap besar 22 .... Question from @indahrahmaputri

izharulhaq78 $d_1=5,5cm \\ d_2=22cm \\ F_2=8000N$

$F_1=?$

$\frac{F_1}{F_2}= \frac{A_1}{A_2} \\\frac{F_1}{F_2}= \frac{ \pi \frac{d_1^2}{4} }{ \pi\frac{d_2^2}{4}} \\ \frac{F_1}{F_2}= \frac{d_1^2}{d_2^2} \\ \frac{F_1}{8000}= \frac{ \frac{55}{10}(\frac{55}{10})}{22(22)} \\ \frac{F_1}{8000}= \frac{55}{10}(\frac{55}{10})(\frac{1}{22})(\frac{1}{22}) \\ \frac{F_1}{8000}= \frac{1}{2}(\frac{1}{2})(\frac{1}{2})(\frac{1}{2}) \\\frac{F_1}{8000}= \frac{1}{16} \\ \frac{F_1}{500}= \frac{1}{1} \\ F_1=500N$

adib245 Perbandingan luas
A1 : A2
π2,75 x 2,75 : π11 x 11
7,5625 : 121
1 : 16
maka A1 = 1
A2 : 16
F2 = 8 kilo newton = 8000 N
F1?

A1/F1 = A2/F2
1/F1 = 16/8000
F1 = 1 x 8000/16 = 500 N (d)

Please, kasih jawaban secepatnya ya... apa tujuan Mpu Sindok memindahkan pusat pemerintahan dari Jwa Tengah ke Jawa Timur ? Jelaskan !

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