ImmanuelSinagaYang diketahui : R = 8 cm bayangan : nyata s' = 12 cm t = 2 cm
maka : F = 1/2R = 1/2 x 8 cm = 4 cm
a. Jarak Benda(s) : 1/s = 1/f - 1/s' = 1/4 - 1/12 = 1/6 s = 6 cm
b. Perbesaran(M) M = s'/s = 12cm/6 cm = 2 kali
c. Tinggi bayangan(t') : t' = M x t = 2 x 2 cm = 4 cm
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micodla
Dik : R = 8 cm, maka f = 4 cm s' = 12 cm h = 2 cm Dit : s, M, h' Jawab : a. 1/f = 1/s + 1/s' b. M = s'/s c. M = h'/h -1/s = 1/s' -1/f M = 12/6 2 = h'/2 -1/s = 1/12 - 1/4 M = 2 kali h' = 4 cm -1/s = -2/12 s = 6 cm
R = 8 cm
bayangan : nyata
s' = 12 cm
t = 2 cm
maka :
F = 1/2R = 1/2 x 8 cm = 4 cm
a. Jarak Benda(s) :
1/s = 1/f - 1/s'
= 1/4 - 1/12
= 1/6
s = 6 cm
b. Perbesaran(M)
M = s'/s = 12cm/6 cm = 2 kali
c. Tinggi bayangan(t') :
t' = M x t
= 2 x 2 cm
= 4 cm
s' = 12 cm
h = 2 cm
Dit : s, M, h'
Jawab :
a. 1/f = 1/s + 1/s' b. M = s'/s c. M = h'/h
-1/s = 1/s' -1/f M = 12/6 2 = h'/2
-1/s = 1/12 - 1/4 M = 2 kali h' = 4 cm
-1/s = -2/12
s = 6 cm
Semoga membantu ... :-)