Sebuah cermin cekung memiliki jarak fokus 40 cm sebuah benda yg tingginya 15 cm diletakan sejauh 120 cm didepan cermin tentukan: a.jarak bayangan b.perbesaran bayangan c.tinggi bayangan pakai diketahu dan caranya
DwitasariP
F = 40 cm h = 15 cm s = 120 cm a. s' ... ? 1/f = 1/s + 1/s' 1/40 = 1/120 + 1/s' 1/40 - 1/120 = 1/s' 3-1/120 = 1/s' 2/120 = 1/s' s' = 120/2 = 60 cm b. M....? M = s'/s = 60/120 = 1/2 kali c. h'....? M = h'/h 1/2 = h'/15 2h' = 15 h' = 7,5 cm
h = 15 cm
s = 120 cm
a. s' ... ?
1/f = 1/s + 1/s'
1/40 = 1/120 + 1/s'
1/40 - 1/120 = 1/s'
3-1/120 = 1/s'
2/120 = 1/s'
s' = 120/2
= 60 cm
b. M....?
M = s'/s
= 60/120
= 1/2 kali
c. h'....?
M = h'/h
1/2 = h'/15
2h' = 15
h' = 7,5 cm