Sebuah benda tingginya 1 cm di depan cermin cekung sehingga terjadi bayangan nyata setinggi 3 cm. jika jarak fokus cermin 10 cm, hitunglah jarak benda dan jarak bayangan benda..
pramuditaevelyn
Ho = 1cm hi = 3cm f = 10 cm so? M = 3/1 = 3x si = 3. so = 3so 1/f = 1/3so + 1/so 1/10 = 1/3so + 1/so 1/10 = 1/3so + 3/3so 1/10 = 4/3so 3so/4 = 10 3so = 10×4 so = 40/3 = 13,334 cm
hi = 3cm
f = 10 cm
so?
M = 3/1 = 3x
si = 3. so = 3so
1/f = 1/3so + 1/so
1/10 = 1/3so + 1/so
1/10 = 1/3so + 3/3so
1/10 = 4/3so
3so/4 = 10
3so = 10×4
so = 40/3 = 13,334 cm