Sebuah benda terletak 12 cm di depan cermin cekung yg jarak fokusnya 8 cm.jika tinggi benda 2cm,tentukan jarak bayangan,sifat bayangan,dan perbesarannya?
Asruul
Diketahui = S₀ = 12 cm f = 8 cm h₁ = 2 cm Ditanya = S₁, Sifat dan M Jawab 1/S₁ = 1/f - 1/S₀ 1/S₁ = 1/8 - 1/12 1/S₁ = 3 - 2/24 1/S₁ = 1/24 S₁ = 24 cm
Sifat Nyata, terbalik, diperbesar
M = | S₁/S₀ | M = | 24/12 | M = 2 Kali
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ybie
Jarak bay= si si= soxf/ so-f = 12 x 8/4 = 24 sifat bay= nyata terbalik diperbesar perbesaran= 24/12 = 2x
f = 8 cm
h₁ = 2 cm
Ditanya = S₁, Sifat dan M
Jawab
1/S₁ = 1/f - 1/S₀
1/S₁ = 1/8 - 1/12
1/S₁ = 3 - 2/24
1/S₁ = 1/24
S₁ = 24 cm
Sifat
Nyata, terbalik, diperbesar
M = | S₁/S₀ |
M = | 24/12 |
M = 2 Kali
si= soxf/ so-f = 12 x 8/4 = 24
sifat bay= nyata terbalik diperbesar
perbesaran= 24/12 = 2x