Question

Sebuah benda setinggi 10cm berada didepan lensa cekung dengan jarak 30cm. jika jarak fokus lensa 20cm ,perbesaran bayangan adalah ....kali

Answer 1

Diketahui = h₀ = 10 cm
                 S₀ = 30 cm
                    f = 20 cm
DItanya = M ?
Jawab =
1/S₁ = 1/f - 1/S₀
1/S₁ = 1/20 - 1/30
1/S₁ = 3+2/60
1/S₁ = 4/60
   S₁ = 15 cm

M = | S₁/S₀ |
M = | 15/60 |
M = 0,25 Kali

Answer 2

Dik: ho: 10 cm
so: 30 cm
f: 20 cm
dit: m =?
dij:
1/si = 1/f - 1/so
1/si = 1/20 - 2/30
1/si = 3/60 - 2/60
1/si = 1/60
si/1 = 60/1
= 60

m = | si/so |
= | 60/30 |
= 2 kali