Sebuah benda bermassa 2kg jatuh bebas dari ketibggian 20m dari atas tanah. besarnya perubahan energi potensial setelah benda bergerak selama 1 s adalah...?
97agus
Diket: m=2 kg h1=20 m h2=1/2.g.t^2=1/2.10.1^2=5 m g=10 m/s^2 dit: ΔEp=..? ΔEp=m.g.(h1-h2) ΔEp=2.10.(20-5) ΔEp=20.15 ΔEp=300 J
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pelajarsederhana
Diketahui : m = 2kg h₀ = 20m g = 10m/s Ditanya : Ep? Pertama, cari h saat 1 sekon : h₁ = 1/2 x g x t² h = 1/2 x 10 x 1² h = 5 --> h = 20-5 = 15m Ep = m x g x h Ep = 2 x 10 x 15 Ep = 300 Joule
m=2 kg
h1=20 m
h2=1/2.g.t^2=1/2.10.1^2=5 m
g=10 m/s^2
dit: ΔEp=..?
ΔEp=m.g.(h1-h2)
ΔEp=2.10.(20-5)
ΔEp=20.15
ΔEp=300 J
m = 2kg
h₀ = 20m
g = 10m/s
Ditanya : Ep?
Pertama, cari h saat 1 sekon :
h₁ = 1/2 x g x t²
h = 1/2 x 10 x 1²
h = 5
--> h = 20-5 = 15m
Ep = m x g x h
Ep = 2 x 10 x 15
Ep = 300 Joule