Sebuah benda berjarak 20cm di depan cermin cekung memiliki fokus 10cm.perbesaran bayangan yg dihasilkan adalah..
salmanada
Dik : So = 20 cm f = 10 cm Dit : Perbesaran (M)? Jawab : -> 1/Si = 1/f - 1/So 1/Si = 1/10 - 1/20 1/Si = 2-1/20 1/Si = 1/20 Si = 20/1 = 20 cm ~> M = Si/So = 20/20 = 1 kali
1 votes Thanks 1
GusAgung
Diketahui : s= 20 cm f =10 cm ditanya : M = ............ ? jawab : 1/s + 1/s' = 1/f 1/ 20 cm + 1/s' = 1/10 cm 1/s' = 1/10 cm - 1/20 cm 1/s' = 2/20 cm - 1/20 cm 1/s' = 1/ 20 cm s' = 20 cm M = s' / s M = 20 cm / 20 cm M = 1 maaf jika salah dan semoga benar.
f = 10 cm
Dit : Perbesaran (M)?
Jawab :
-> 1/Si = 1/f - 1/So
1/Si = 1/10 - 1/20
1/Si = 2-1/20
1/Si = 1/20
Si = 20/1 = 20 cm
~> M = Si/So
= 20/20 = 1 kali
s= 20 cm
f =10 cm
ditanya :
M = ............ ?
jawab :
1/s + 1/s' = 1/f
1/ 20 cm + 1/s' = 1/10 cm
1/s' = 1/10 cm - 1/20 cm
1/s' = 2/20 cm - 1/20 cm
1/s' = 1/ 20 cm
s' = 20 cm
M = s' / s
M = 20 cm / 20 cm
M = 1
maaf jika salah dan semoga benar.