Sebuah belah ketupat ABCD dengan titik potong kedua diagonalnya O. panjang AB=(3x-7) cm dan CD=(2x+2) cm. berapakah panjang sisi belah ketupat tersebut ?
Beta27
Pajang sisi belah ketupat sama panjang maka AB = CD 3x - 7 = 2x + 2 3x - 2x -7 + 7 = 2x - 2x + 2 + 7 x = 9
maka panjang sisi AB = 3x - 7 = 3(9) - 7 = 27-7 = 20 cm CD = 2x + 2 = 2(9) + 2 = 18 + 2 = 20 cm
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zurratul AB = CD 3x - 7 = 2x + 2 3x - 2x -7 + 7 = 2x - 2x + 2 + 7 x = 9. jadi AB = 3x - 7 = 3(9) - 7 = 27-7 = 20 cm CD = 2x + 2 = 2(9) + 2 = 18 + 2 = 20 cm
maka
AB = CD
3x - 7 = 2x + 2
3x - 2x -7 + 7 = 2x - 2x + 2 + 7
x = 9
maka panjang sisi
AB = 3x - 7 = 3(9) - 7 = 27-7 = 20 cm
CD = 2x + 2 = 2(9) + 2 = 18 + 2 = 20 cm
AB = CD
3x - 7 = 2x + 2
3x - 2x -7 + 7 = 2x - 2x + 2 + 7
x = 9. jadi
AB = 3x - 7 = 3(9) - 7 = 27-7 = 20 cm
CD = 2x + 2 = 2(9) + 2 = 18 + 2 = 20 cm