Sebuah balok dengan panjang : lebar : tinggi = 3:2:1. Jika luas permukaan balok 550 m^2, panjang, lebar, dan tinggi balok tersebut berturut turut adalah...
2(pL +pT+ lT ) = LPermukaan 2(3x*2x+ 3x*x + 2x*x) = 550 6x² + 3x² + 2x² = 550/2 11x² = 275 x² = 275/11= 25 x =√25 = 5 maka P = 3x= 3(5)= 15m L= 2x= 2(5) = 10 m T= x = 5 m
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Priscillayp
LP = 2(pL +pT+ lT ) 550 = 2(3X x 2X+ 3X x X + 2X x X) 550/2 = 6X² + 3X² + 2X² 11X² = 275 X² = 275/11= 25 X =√25 = 5 jadi.. P = 3X = 3 x 5 = 15 m L = 2X = 2 x 5 = 10 m T = X = 5 m
2(pL +pT+ lT ) = LPermukaan
2(3x*2x+ 3x*x + 2x*x) = 550
6x² + 3x² + 2x² = 550/2
11x² = 275
x² = 275/11= 25
x =√25 = 5
maka
P = 3x= 3(5)= 15m
L= 2x= 2(5) = 10 m
T= x = 5 m
550 = 2(3X x 2X+ 3X x X + 2X x X)
550/2 = 6X² + 3X² + 2X²
11X² = 275
X² = 275/11= 25
X =√25 = 5
jadi..
P = 3X = 3 x 5 = 15 m
L = 2X = 2 x 5 = 10 m
T = X = 5 m