Question

Sebuah balok bermassa m = 9 kg

Answer 1

Verified answer

Hk. II Newton

m = 9 kg
μₛ = ⅓
tan θ = ¾ ⇄sin θ = ⅗ ⇄cos θ = ⅘
g = 10 m/s² ... anggap

Gaya yang bekerja pada sumbu Y

Σ Fy = 0
N - (w + F sin θ) = 0
N = w + F sin θ

Benda Tepat akan bergerak :
Σ F = 0
Fₘᵢₙ - fₛ = 0
Fₘᵢₙ = fₛ
F cos θ = μₛ (mg + F sin θ)
⅘ F = (⅓) [(9) (10) + ⅗ F]
F = 50 N ... jawab