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Verified answer
Jawaban :T₁ = 127 ºC = 400 K P₁ = 40 W
T₂ = 327 ºC = 600 K P₂ = ___ ?
P = e σ T⁴ A
P₂ / P₁ = (e σ T₂⁴ A) / (e σ T₁⁴ A)
P₂ / P₁ = T₂⁴ / T₁⁴
P₂ = P₁ · (T₂ / T₁)⁴
P₂ = (40 W) · (600 / 400)⁴
P₂ = (40 W) · (3 / 2)⁴
P₂ = (40 W) · 81 / 16
P₂ = 202,5 W ←
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