Bimago
NaOH+ CH3COOH ---> CH3COONa + H2O M 5 mmol 5 mmol - - B 5 mmol 5 mmol 5 mmol 5 mmol S - - 5 mmol 5 mmol
[OH¯] = akar kw/ka . M garam = akar 1 x 10¯¹⁴/ 1x10¯5 . mmol garam /v. tot = akar 1 x 10¯9 5/100 = akar 5 x 10¯¹¹ = 5½ x 10¯55 poh = - log ( 5 ½ c 10¯5,5) = 5,5 - ½ log 5 = 5,5 - 0,35 = 5,15 ph = pkw - poh = 14 - 5,15 = 8,85
M 5 mmol 5 mmol - -
B 5 mmol 5 mmol 5 mmol 5 mmol
S - - 5 mmol 5 mmol
[OH¯] = akar kw/ka . M garam
= akar 1 x 10¯¹⁴/ 1x10¯5 . mmol garam /v. tot
= akar 1 x 10¯9 5/100
= akar 5 x 10¯¹¹
= 5½ x 10¯55
poh = - log ( 5 ½ c 10¯5,5)
= 5,5 - ½ log 5
= 5,5 - 0,35
= 5,15
ph = pkw - poh
= 14 - 5,15
= 8,85