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v ch3cooh= 50 ml
M ch3cooh= 50M
nNaoh= 1 mmol
v = 50 ml
M= 50 M
vtotal= 100 ml
ka= 1x10^-5
ch3cooh(aq) + naoh (aq) -> nach3coo (aq) + h2o(l)
1 1 - -
1 1 1 1
- - 1 1
nach3coo -> na(+) + ch3coo(-)
1 1 1
ch3coo + h2o -> <-ch3cooh + oh
1
kw/ka= [ch3cooh][oh]/ch3coo]
10^-14/10^-5=[oh]^2/1/100
10^-9=[oh]^2/1x10^-2
10^-9 x 10^-2= [oh]^2
10^-11=[oh]^2
[oh]= 10^-5.5
poh= 5.5
ph= 14- 5.5 = 8.5